### Know what kind of math section you're working on

There are three different kinds of SAT math sections, and it's important to know which kind you're working on. Lucky for you, it's super easy to check without even having to flip through the section. Just look to the top of the first page of the section to see how many questions there are.

If the first page tells you there are 20 questions, then they'll all be multiple choice, and go from easy to hard. By number 16 or 17, you'll probably be into difficulty 4 or 5 questions.

If the first page tells you there are 18 questions, it's a grid-in section. Questions 1–8 will be multiple choice and get increasingly difficult—numbers 7 and 8 will probably be difficulty 4 or 5. Questions 9–18 will be grid-in questions; they will start easy and become increasingly difficult again—numbers 16–18 are likely to be difficulty 4 or 5.

Grid-in sections are the important ones to identify—they're the reason I wrote this post. If you're doing any strategic skipping, recognizing grid-in sections is of paramount importance. Even if you're not planning to do any strategic skipping, you should be conscious of how much time you're spending on hard questions 7 and 8 while easy grid-in questions remain unanswered. Remember, easy questions are more important than hard ones.

The last math section will be section 8, 9, or 10, and will always be 16 multiple choice questions, going from easy to hard once. This section will be 20 minutes instead of 25 (for regular time students). Questions 14–16 will probably be difficulty 4 or 5.

1. Just don't forget to go back and do 7/8 if you choose to skip it!

In any case, would you recommend temporarily skipping 7/8 and going back to it, just to get the easy questions out of the way?

2. That's one of my first recommendations when students are struggling with time and/or accuracy.

3. Ahh...look more closely at that top left set of *s. Those can't be 60Âº...

4. Gotcha. Those two form a supplementary angle. I guess the *s were just markings and not variables. Thanks!

5. Right...just markings. Instead of focusing on how many *s you see, focus on how many 180Âºs they create.

6. I'm not sure—I think each element needs to be there to hit a top score. Take a really well-organized essay with a well-developed thesis, and put a grammatical error in every sentence. There's no way it gets a high score.

7. Hey Mike. I'm really struggling with finding the Essay tumblr password? I've repeatedly tried to log in using the 4th word on pg. 27. When I gave the book to my parents and asked them to read the directions and find the word, they found the same one. Could you please help me find the password somehow?

8. If your looking for dozens of test and free e-prepbooks.... visit http://officialsatexams.com

9. Thanks for such a great information about SAT exam. I am already preparing for SAT entrance exam.

10. Here's the important thing to know about this problem: everywhere you see a dotted or solid line, that's an edge. Everywhere edges meet, that's a vertex.

There are 3 segments connected to vertex A, so there are 3 other vertices connected vertex A by an edge. There are 13 vertices you could draw a line to from A. Of those, 3 of them are connected by an edge. That leaves 10 segments you could draw connecting other vertices to A that wouldn't lie along edges.

BTW, I don't know where you got this problem, but it's basically copycatting Blue Book page 717 # 17.

11. Hey, how do you do number 15? I've tried many times and cant get 10 radical 2, only 10

12. If you draw a line straight down from D, and also draw D, then you'll have a right triangle with legs 10 and 10. That's an isosceles right (AKA 45Âº-45Âº-90Âº) triangle, so its hypotenuse must be 10√2.

13. can you do number 6 please ?

14. All 12 students, with an average score of 74, have a total score of 12 × 74 = 888.

The 4 students who had an average of 96 have had a total score of 4 × 96 = 384.

So the other 8 students must have a total score of 888 – 384 = 504. Since there are 8 of them, their average score is 504/8 = 63.

15. can you please explain 16?

16. Parallel lines have equal slopes, so first you need to figure out the slope of the original line by putting it into y = mx + b form. When you do that, you'll see that you're looking for a slope of 2/3.

From there, just put each pair of points into the slope formula until you get a slope of 2/3.

17. Genevieve KennebeckMarch 3, 2014 at 11:07 AM

Could you explain #7 to me please?

18. For one of those answer choices, all the values in the table will be true. So you have to test each one until you get one that works for all three.

Start with (A). The table says f(2) must be 11, but when you test (A), you get:

f(2) = 8(2) – 7
f(2) = 16 - 7
f(2) = 9

That doesn't work, so you can eliminate (A).

Try (B):

f(2) = 5(2) + 1
f(2) = 11

That works, so try the next set of numbers from the table. The table says f(3) = 16. That works with (B) too!

f(3) = 5(3) + 1
f(3) = 16

Unfortunately, (B) fails on the last set of values. The table says f(4) = 23, but according to (B)...

f(4) = 5(4) + 1
f(4) = 21

So we get rid of (B) and move on.

(C) gets broken right away—all of the values given by (C) will be negative, so none of them will match the table.

Try (D) now.

f(2) = 2^2 + 7 = 11
f(3) = 3^2 + 7 = 16
f(4) = 4^2 + 7 = 23

They all work! That's why (D) is the answer.

Does that help?